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A local variable is not a member of a type and represents local storage rather than the state of an instance of a given type Java also requires this because it prevents the presence of orphaned variables. This is all very abstract, however.

3 local variables are non existent in the memory after the function termination Historically, when a new variable was created it would contain random values from the memory [and one could not predict the value] However static variables remain allocated in the memory throughout the life of the program irrespective of whatever function

Additionally from your question, static variables can be declared locally in class or function scope and globally in namespace or file scope.

To access a global variable within a function you must specify it with global Otherwise, the variable inside the function is a local variable that only has utility inside that function. If you set the value of a variable inside the function, python understands it as creating a local variable with that name This local variable masks the global variable.

I think you are using 'global' incorrectly You should declare variable without global and then inside the function when you want to access global variable you declare it global yourvar. Roughly speaking, an instance variable represents a property of a specific object In the following example, lx is a local variable, local to the method greet

Gx is a global variable accessible anywhere in the module, ix is an instance variable that could have a unique value for each instance of the object.

When python interprets your function, it identifies all variables you modify in the function and creates local versions of them Since you don't assign to i until after you modify it, you reference an undefined local variable Either define i inside the function or use global i to inform python you wish to act on the global variable by that name. Local variable 'local' referenced before assignment i searched for this error, and found it usually has to do something with uncorrect scopes.

The local command constrains the variables declared to the function scope With that said, you can deduce that doing so inside an if block will be the same as if you did outside of it, as long as it's inside of a function. 1 local variables and primitives should be initialized before use because you would know what to expect from the values

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